背景：考慮到預約的問題，在預約一個訂單，怎樣確定預約是成功的呢？要是有多個用戶并發去預約一個號源，肯定有沒有預約成功的用戶，那么我怎么確認該用戶預約失敗了呢？在51提問的時候，有人提到了可以通過獲取服務器返回值的狀態碼，來確定是否預約成功。詢問了公司的開發，成功接口返回code：0  失敗返回code:1 。

之后，一直思考怎么解決這個問題，然后看到了如下博文：//bbs.csdn.net/topics/310138356，受益頗深，也解決了問題。具體解決問題如下：

1.錄制一個示例腳本（登錄），腳本內容如下：

Action()
{
    web_url("booking",
        "URL=//192.168.0.99:8081/booking",
        "TargetFrame=",
        "Resource=0",
        "RecContentType=text/html",
        "Referer=",
        "Snapshot=t2.inf",
        "Mode=HTML",
        LAST);

2.進行登錄操作

 lr_think_time(8);

    web_reg_find("Text=chenyinhua",  //檢查點
                 "SaveCount=a",
                 LAST);

    web_submit_data("loginAction!loginQuick.action",
        "Action=//192.168.0.99:8081/booking/loginAction!loginQuick.action",
        "Method=POST",
        "TargetFrame=",
        "RecContentType=text/html",
        "Referer=//192.168.0.99:8081/booking/",
        "Snapshot=t8.inf",
        "Mode=HTML",
        ITEMDATA,
        "Name=orderwebUser.userName", "Value=Y2hlbnlpbmh1YQ==/", ENDITEM,
        "Name=userPassword", "Value=MTIzNDU2", ENDITEM,
        "Name=certCode", "Value=1111", ENDITEM,
        LAST);

    return 0;
}

3.在腳本最開始，定義一個變量，用于判斷登錄是否成功：

int status;

4.將web_submit_data的返回值賦值給status，如下：

status=web_submit_data("loginAction!loginQuick.action",
        "Action=//192.168.0.99:8081/booking/loginAction!loginQuick.action",
        "Method=POST",
        "TargetFrame=",
        "RecContentType=text/html",
        "Referer=//192.168.0.99:8081/booking/",
        "Snapshot=t8.inf",
        "Mode=HTML",
        ITEMDATA,
        "Name=orderwebUser.userName", "Value=Y2hlbnlpbmh1YQ==/", ENDITEM,
        "Name=userPassword", "Value=MTIzNDU2", ENDITEM,
        "Name=certCode", "Value=1111", ENDITEM,
        LAST);

5.寫入一個判斷，輸出status的值：

 if(status==1)        //一旦登錄失敗，腳本給出提示報錯信息
    {
        lr_error_message("錯誤信息：%s","不能正常登錄");
        return -1;
    }else if(status==0){
      lr_output_message("登錄成功。status=%d",status);
      return 0;
    }else{
      lr_output_message("異常");
    }
這里也可以用status的值，來判斷登錄事務是成功還是失敗。

6.所以，整合后的腳本如下：

Action()
{
    int status;    //定義變量，用于判斷登錄是否成功


    web_url("booking",
        "URL=//192.168.0.99:8081/booking",
        "TargetFrame=",
        "Resource=0",
        "RecContentType=text/html",
        "Referer=",
        "Snapshot=t2.inf",
        "Mode=HTML",
        LAST);

7.進行登錄操作

 lr_think_time(8);

    web_reg_find("Text=chenyinhua",
                 "SaveCount=a",
                 LAST);

    status=web_submit_data("loginAction!loginQuick.action",
        "Action=//192.168.0.99:8081/booking/loginAction!loginQuick.action",
        "Method=POST",
        "TargetFrame=",
        "RecContentType=text/html",
        "Referer=//192.168.0.99:8081/booking/",
        "Snapshot=t8.inf",
        "Mode=HTML",
        ITEMDATA,
        "Name=orderwebUser.userName", "Value=Y2hlbnlpbmh1YQ==/", ENDITEM,
        "Name=userPassword", "Value=MTIzNDU2", ENDITEM,
        "Name=certCode", "Value=1111", ENDITEM,
        LAST);


    if(status==1)

8.一旦登錄失敗，腳本給出提示報錯信息

    {
        lr_error_message("錯誤信息：%s","不能正常登錄");
        return -1;
    }else if(status==0){
      lr_output_message("登錄成功。status=%d",status);
      return 0;
    }else{
      lr_output_message("異常");
    }

原文轉載自：